Question

Two dice are thrown simultaneously find the probability of getting the sum as a prime number

Answer 1

We know that in a single throw of two dice, the total number of possible outcome is

(6×6)=36. LET S be the sample space. Then, n(S) =36

Answer 2

sample space : {(1,1);(1,2);(1,3);(1,4);(1,5);(1,6)
(2,1);(2,2);(2,3);(2,4);(2,5);(2,6)
(3,1);(3,2);(3,3);(3,4);(3,5);(3,6)
(4,1);(4,2);(4,3);(4,4);(4,5);(4,6)
(5,1);(5,2);(5,3);(5,4);(5,5);(5,6)
(6,1);(6,2);(6,3);(6,4);(6,5);(6,6)}
n(s): 36
event(A): sum of the no. on the upper phase is a prim number.

A: { (1,1);(1,2);(1,4);(1,6);(2,1);(2,3);(2,5);(3,2),(3,4);(4,1);(4,3);(5,2);(5,6);(6,1);(6,5)}

n(A) : 15

p(A) = n(A)/n(s)
= 15/36

HOPE THIS HELPS YOU!!!!