Question

if the radii of circular ends of a bucket which is 45 cm high are 28 cm and 7 cm find the capacity of the bucket

Answer 1

The shape of bucket is that of a frustum
where R=28 cm
r= 7 cm and h= 45 cm
V =
$\frac{\pi}{3} \times ( {r}^{2} + {r}^{2} + r \times r) \times h$
22/7*3 ×(28×28+7×7+28×7)×45
= 48510