if the radii of the circular ends of a conical bucket which is 32cm high are 40cm and 16cm,find the capacity and total surface area of the bucket
harinireddy:
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36
Answer:
Volume = Capacity = = 83675.42 cubic cm.
Total Surface area = 7844.57 Square cm.
Step-by-step explanation:
Volume of bucket = Volume of the frustum = πh(R^2+Rr+r^2 )/3
Here R = 40 cm
r = 16 cm
h = 32 cm.
Volume of bucket = 22*32*(40*40 + 40*16 + 16*16)/(3*7) = 22 * 32 * 2496/(3*7)
= 83675.42 cubic cm.
The bucket is normally open from the top and closed from bottom. (Add area of bottom circle to lateral surface area)
Hence total surface area = π(R+r)*s+ πr^2
s = Slant height. = √((h^2+(R-r)^2) = √(32^2+(40-16)^2 = 40cm.
Hence Total surface area of the bucket = π(40+16)*40+ π16^2 = 7844.57 Square cm.
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Answer:
Volume of Frustum of cone = 1/3 ×π×r*2 × h
TSA of Frustum of cone = π(R +r ) l + π ( R*2 + r*2 )
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