Question

If the radii of the circular ends of a frustum of height 21cm be 9cm and 3cm then the capacity of the frustum is ​

Answer 1

Answer:

Given h=6 cm,R

1

=9 cm and R

2

=5 cm

Volume of the frustrum of cone =

3

1

πh(R

1

2

+R

2

2

+R

1

R

2

)

volume of the frustrum of cone =

3

1

×π×6((9)

2

+(5)

2

+(9)(5))=302π