Question

if the radii of the ends of a bucket 45 cm high are 28 cm and 7 cm. determine the capacity and total surface area of the bucket

Answer 1

clearly the bucket is in the frustum shape. the smaller radius r=7cm

the larger radius R=28 cm

height h=45 cm

the volume of the bucket =



total surface area of the frustum = curved surface area + area of the base



Answer 2

Answer:

The total surface area of bucket is $\bold{48510 \mathrm{cm}^{3}}$

Step-by-step explanation:

Step 1:

Given Data,  

Height of the bucket (h) = 45 cm

Radius one (R) = 28 cm

Radius a pair of (r) = 7 cm

Volume of solid = $\pi$ / 3 $\mathrm{h}\left(\mathrm{R}^{2}+\mathrm{r}^{2}+\mathrm{R} \times \mathrm{r}\right)$

Step 2:

Where,  

R= larger radius  

r = smaller radius  

h= height

Step 3:

$\Rightarrow \pi / 3 \times 45\left[(28)^{2}+(7)^{2}+28 \times 7\right]$

=> π × 15× [ 784 + 49 + 196 ]

=> π × 15 × 1029

=> π × 15435

=> 22/7 × 15435

=> 22× 2205

=>$48510 \mathrm{cm}^{3}$