if the radio of two circular cylinder are in the ratio 3:4 and their height are in the ratio 6:5 .find the ratio of their curved surface area
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Given,
- The radius of two circular cylinder are in the radius 3:4.
- Their height are in the ratio 6:5.
To Find,
- The ratio of their curved surface area.
According to the question,
We know that,
Curved surface area of cylinder = 2πrh
[ For first cylinder ]
- Radius of first cylinder (r1) = 3r
- Height of first cylinder (h1) = 6h
[ For second cylinder ]
- Radius of second cylinder (r2) = 4r
- Height of second cylinder (h2) = 5h
Now,
Ratio = CSA of first cylinder / CSA of second cylinder
↪ Ratio = 2πr1h1 / 2πr2h2
[ Put the values ]
↪ Ratio = 2π(3r)(6h) / 2π(4r)(5h)
↪ Ratio = 18rh / 20rh
↪ Ratio = 18/20
↪ Ratio = 9/10
↪ Ratio = 9 : 10
Therefore,
The ratio of their curved surface area is 9 : 10.
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