If the radius and the height of a cone both are increased by 10% then the volume of the cone increases by ____. Give answer by explanation.
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Volume of cone = πr²h/3
New radius = 11r/10
new height = 11h/10
So new V = π(11r/10)²)(11h/10)(1/3)
= π(121r/100)(11h/10)(1/3)
= π 1331rh/3000
Percentage increase = (New volume/Old volume * 100) -100
= (π/3 * 3/π *1331/1000 * rh/rh * 100) -100
= (1331/1000 * 100) -100
= 133.1 -100
= 33.1%
New radius = 11r/10
new height = 11h/10
So new V = π(11r/10)²)(11h/10)(1/3)
= π(121r/100)(11h/10)(1/3)
= π 1331rh/3000
Percentage increase = (New volume/Old volume * 100) -100
= (π/3 * 3/π *1331/1000 * rh/rh * 100) -100
= (1331/1000 * 100) -100
= 133.1 -100
= 33.1%
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