Question

If the radius of a circle is 4cm and the length of a chord of the circle is 6cm then the distance of the chord from the centre is ​

Answer 1

Answer:

Give OC =4 cm, Chord AB =6 cm

∵OC⊥AB⇒bisectsAB

⇒AC=CB=3cm

∴InOCA,OA

2

+AC

2

(PythagorasTheorem)

=4

2

+3

2

=16+9=25

⇒OA=5cm

Let EF be the chord at a distance of 3cm from the centre.

GIven, radius=OE =5 cm

∴In△OGE,EG

2

=OE

2

−OG

2

=5

2

−3

2

=25−9=16

⇒EG=4cm

∴EF=2×EG=8cm

(Line from centre ⊥ to chord bisects the chord )

Step-by-step explanation:

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