If the radius of a circle is decreased by 50%, its area is decreased by:
A. 75%. B. 50%
C. 85%. D. 65%
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Hey dear ☺️
Here your answer
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
➡️Suppose
Old radius of circle is r
And new radius is R
Old area of circle = πr²
&
New area of circle = πR²
But we have given that new radius have decrease 50% to new radius
so we can write that R = r/2
so....
new area of circle = π (r/2)²
= πr²/4
= 0.25 πr²
=> πr²-0.25 πr²= 0.75 πr²
your answer= 0.75×100=75℅
Here your answer
⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️
➡️Suppose
Old radius of circle is r
And new radius is R
Old area of circle = πr²
&
New area of circle = πR²
But we have given that new radius have decrease 50% to new radius
so we can write that R = r/2
so....
new area of circle = π (r/2)²
= πr²/4
= 0.25 πr²
=> πr²-0.25 πr²= 0.75 πr²
your answer= 0.75×100=75℅
soniasinghal731:
Thanks for answering
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