If the radius of a circle is increased by 16 its area increases by
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Answer:
Step-by-step explanation:
Let the radius of Circle A be r. Its area =(pi)r^2.
Next, let the radius of Circle B be 1.16r. Its area =(pi)(1.16r)^2 = 1.3456(pi)r^2.
So the area of Circle B is 1.3456 times that of the area of Circle A.
The area increases by 34.56% on increasing the radius by 16%
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Step-by-step explanation:
The area increases by 34.56% on increasing the radius by 16%. What will be the increase in percentage of an area of a circle if its radius is increased by 16(2/3)%? If the radius of a circle is increased by 15 percent, by how much is its area increased? The radius of a circle is increased by 1%.
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