If the radius of a cone is doubled and the height is tripled, what happens to the volume?
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Volume of cone = 1 / 3 pi r^2h
Given r is doubled
And height is tripled
New volume = 1 / 3 pi ( 2r ) ^2 × 3h
1 / 3 pi 4r^2 × 3h
On dividing Old and New volume
we will get 12
Hence the volume is increased by 12 times.
Hope it helps you.
Given r is doubled
And height is tripled
New volume = 1 / 3 pi ( 2r ) ^2 × 3h
1 / 3 pi 4r^2 × 3h
On dividing Old and New volume
we will get 12
Hence the volume is increased by 12 times.
Hope it helps you.
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