If the radius of a right circular cylinder is decreased by 50% and its height is increased by 60%,its volume will be decreased by
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Answer:
original volume=πr^2h
if r decreased by 50%
new r=r/2=0.5r
if height increases by 60%
new heigt=h+60%of h=h+0.6h=1.6h
new volume=π(0.5r) ^2(1.6h) =π×0.25r^2 × 1.6h=0.4πr^2h
decrease =πr^2h - 0.4πr^2h=0.6πr^2h
decrease% = (0.6πr^2h÷ πr^2h) ×100= 60%
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