Question

if the radius of a right circular cylinder open at both the ends is decreased by 25% and the height of the cylinder is increased by 25% in the surface area of the cylinder thus formed is what

Answer 1

Answer:

let radius be r

height be h

old volume=$\pi$$r^{2}$ h

now it is, $\pi (3r/4)^{2}$7h/4= $\frac{22}{7}$*$\frac{9}{16} *\frac{7}{4}$= please solve urself

thanks!!

Step-by-step explanation: