Math, asked by pritamrai172, 1 year ago

If the radius of a sphere is doubled, then what percent of its volume is increased?

Answers

Answered by Anonymous
44
Let radius of sphere = r 
Volume                    = 4πr³/3

Increased radius     = 2r 

Increased volume   = 4π(2r)³)/3
                               = 32πr³/3

difference 

4πr³/3 - 32πr³/3

4πr³(1/3 - 8/3 )

4πr³(-7/3)

-28πr³/3 amount of volume decreased 

magnitude = 28πr³/3 increased 


let p % of 4πr³/3  is 28πr³/3 
4pπr³/300 = 28πr³/3 

p/100        = 7

p               = 700 

P = 700 % 

Increased % = 700%

Answered by sabitnajeeb321
10

Answer:

Step-by-step explanation:

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