If the radius of a sphere is doubled, then what percent of its volume is increased?
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Answered by
44
Let radius of sphere = r
Volume = 4πr³/3
Increased radius = 2r
Increased volume = 4π(2r)³)/3
= 32πr³/3
difference
4πr³/3 - 32πr³/3
4πr³(1/3 - 8/3 )
4πr³(-7/3)
-28πr³/3 amount of volume decreased
magnitude = 28πr³/3 increased
let p % of 4πr³/3 is 28πr³/3
4pπr³/300 = 28πr³/3
p/100 = 7
p = 700
P = 700 %
Increased % = 700%
Volume = 4πr³/3
Increased radius = 2r
Increased volume = 4π(2r)³)/3
= 32πr³/3
difference
4πr³/3 - 32πr³/3
4πr³(1/3 - 8/3 )
4πr³(-7/3)
-28πr³/3 amount of volume decreased
magnitude = 28πr³/3 increased
let p % of 4πr³/3 is 28πr³/3
4pπr³/300 = 28πr³/3
p/100 = 7
p = 700
P = 700 %
Increased % = 700%
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10
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