If the radius of a sphere is increased by 100% then its volume and surface area will be increased by
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Answered by
139
The radius is increased by 100 % means it is doubled so
if initial radius = r then new radius = 2r
Initial volume = 4 × pi × r^3
New volume = 4 × pi × 8r^3
so volume increased by 8 times
similarly surface area increases by 4 times
if initial radius = r then new radius = 2r
Initial volume = 4 × pi × r^3
New volume = 4 × pi × 8r^3
so volume increased by 8 times
similarly surface area increases by 4 times
Answered by
177
radius=r
New Radius,R=2r
New Volume=(4πR^3)/3=(4π(2r)^3)/3
=(32πr^3)/3
Volume increased=((32πr^3)/3)/((4πr^3)/3)
=8 times
=800%
SURFACE AREA=4πR^2=4π(2r)^2=16πr^2
Increase percent=16πr^2/4πr^2=4 times
=400%
Hope it helped you& any problem i may help you
pls mark it as brainliest
New Radius,R=2r
New Volume=(4πR^3)/3=(4π(2r)^3)/3
=(32πr^3)/3
Volume increased=((32πr^3)/3)/((4πr^3)/3)
=8 times
=800%
SURFACE AREA=4πR^2=4π(2r)^2=16πr^2
Increase percent=16πr^2/4πr^2=4 times
=400%
Hope it helped you& any problem i may help you
pls mark it as brainliest
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