If the radius of a sphere is increased by 20% then volume will be increased by....
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Let the radius be = r
The volume = 4πr³/3
When the radius is increased by 20%
The new radius is r+20*r/100 =1.2r
The new volume is = 4π(1.2r)³/3 = 1.728*(4πr³/3)
The %increase in volume = (1.728(4πr³/3)-4πr³/3)*100/(4πr³/3)=72.8%
The volume will increase by 72.8%
The volume = 4πr³/3
When the radius is increased by 20%
The new radius is r+20*r/100 =1.2r
The new volume is = 4π(1.2r)³/3 = 1.728*(4πr³/3)
The %increase in volume = (1.728(4πr³/3)-4πr³/3)*100/(4πr³/3)=72.8%
The volume will increase by 72.8%
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