if the radius of clyinder is doubled then how much percent volume is increase
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calculate it by using 4/3×3.14×r×r×r
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The formula for the volume of cylinder is V = πrsquareh. So r is same value , and then we double it , what happens to the volume ? Let's say original r= x and doubled r =2x.
Original volume =π(x) square =πhrsquare
The new volume after doubling r would be π(2x) square h=4πhx
The new volume would be 4 times the original.
I hope it helps .....
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