If the radius of curvature of a lens is 30cm,then what is its focal length
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Answered by
5
Answer:
Correct option is
C
1.33
(1/f)=(n−1)(
R
1
1
−
R
2
1
)
put R
2
→∞ for plane surface
and R
1
=10cm with f=30cm
we get refractive index n=4/3=1.33
Option c is correct.
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