Question

If the radius of earth shrinks by 2% and its mass, the acceleration due to gravity on the surface of would?​

Answer 1

Answer:

The acceleration due to gravity at the surface of earth is g = G m / R2 .

The radius of eath decreases by 2 %, therefore

R' = R - 0.02 R = 0.98R.

Now acceleration due to gravity will be :

g' = GM / ( 0.98 R )2 = 1.04 g

Percentage increase in acceleration due to gravity

[(g' - g )/g ] x 100 = 4 %

I hope this clarifies your doubt.

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