Question

if the radius of the base and the height of a right cirucular cone are 9cm and 15cm respectively , then the volume of the cone​

Answer 1

Answer:

Hey mate here is ur answer

Step-by-step explanation:

$volume \: of \: the \: come \: = \frac{1}{3} \pi {r}^{2} h \\ = \frac{1}{3} \times \frac{22}{7} \times {9}^{2} \times 15 \\ = \frac{22}{7} \times 27 \times 1 5 \\ = 1272.85 {cm}^{2}$

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Answer 2

$\bf{\underline{\huge{\boxed{\sf{\green{Answer:}}}}}}$

$\bf{\underline{\underline{\rm{\blue{Given:}}}}}$

• Radius of the base = 9cm
• Height of the cone = 15cm

$\bf{\underline{\underline{\rm{\blue{To\:find:}}}}}$

• The volume of the cone

$\bf{\underline{\underline{\rm{\blue{Solution:}}}}}$

We know that volume of cone is calculated using the formula,

$\bf{\underline{\large{\boxed{\sf{\orange{Volume\:of\:cone\:=\:\frac{1}{3}\pi\:r^2h}}}}}}$

Plug in the values,

=> Volume = ⅓ × 3.14 × 9² × 15

=> Volume = ⅓ × 3.14 × 9 × 9 × 15

=> Volume = $\frac{3.14}{3}$ × 9 × 9 × 15

=> Volume = 3.14 × 3 × 9 × 15

=> Volume = 3.14 × 27 × 15

=> Volume = 3.14 × 405

=> Volume = 1271.7

$\bf{\underline{\large{\boxed{\sf{\green{Volume\:of\:cone=\:1271</p><p>7\:cm^3}}}}}}$