Question

if the radius of the base is doubled keeping the height constant .then the ratio of the volume of the larger cone to the smaller cone.

Answer 1

when we take height=h and radios of base=r
then volume of cone=πr^2h/3

if radios of the base is doubled then R=2r
and height=h
so, volume is =π(2r)^2h/3
therefore, ratio of the volume of latter cone to the smaller cone = πr^2h/3/π(2r)^2h/3
=r^2/4r^2
=1/4
=1:4 Answer

Answer 2

the volume of larger cone =r÷2