if the radius of the base is doubled keeping the height constant .then what is the volume
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6
I think it's a cylinder...
Volume of cylinder = πr²h
Radius is doubled, new radius = 2r
New Volume = π(2r)²h = 4πr²h
Volume of cylinder = πr²h
Radius is doubled, new radius = 2r
New Volume = π(2r)²h = 4πr²h
Answered by
0
When the radius is doubled there the volume too would be doubled
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