if the radius of the base of a cone be doubled, its volume becomes?
schauhan:
4 times more
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4 times the original one
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Let height of cone remain constant.
Volume of cone is : (1/3) (pi)(r^2)(h) where h is height of cone and r is radius of the base of cone
Thus we can say tht "Volume is directly proportional to r^2 for constant height"
Therefore, v=r^2
Now if radius of base is doubled then "Volume(V) becomes (2r)^2 i.e V=4(r^2) Thus V=4v.
Volume of cone is : (1/3) (pi)(r^2)(h) where h is height of cone and r is radius of the base of cone
Thus we can say tht "Volume is directly proportional to r^2 for constant height"
Therefore, v=r^2
Now if radius of base is doubled then "Volume(V) becomes (2r)^2 i.e V=4(r^2) Thus V=4v.
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