If the radius of the earth shrinks by 1.5% (mass remaining same), then the value of acceleration due to gravity changes by [BHU 1997]
A) 1% B) 2% C) 3% D) 4%
Answers
Answered by
262
Hey.
Here is the answer.
g = G M / R^2
as, R is decreased by 1.5%
So, new Radius , R' = R - 0.015 R = 0.985R
So, new g, g' = G M / (0.985R)^2
= 1.0306 G M/ R^2
So, change = 0.0306
% change = 3 % (approx)
Thanks .
Here is the answer.
g = G M / R^2
as, R is decreased by 1.5%
So, new Radius , R' = R - 0.015 R = 0.985R
So, new g, g' = G M / (0.985R)^2
= 1.0306 G M/ R^2
So, change = 0.0306
% change = 3 % (approx)
Thanks .
Answered by
63
here is your answer
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