If the radius of the octahedral void is r and the radius of the atoms in the close packing is R, derive relationship between r and R.
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Answered by
38
Let take r and R are the radii of the octahedral site and atoms respectively,
then use Pythagoras theorem we get
(2R)2 = (R+r)2 +(R+r)2
4R2 = 2(R+r)2
Divide by 2 we get
2R2 = (R+r)2
Take root both side we get
R√2 =R+r
R√2 – R = r
r = R(√2–1)
value of √2= 1.414
r = R(1.414–1)
r = 0.414 R
then use Pythagoras theorem we get
(2R)2 = (R+r)2 +(R+r)2
4R2 = 2(R+r)2
Divide by 2 we get
2R2 = (R+r)2
Take root both side we get
R√2 =R+r
R√2 – R = r
r = R(√2–1)
value of √2= 1.414
r = R(1.414–1)
r = 0.414 R
Answered by
7
Answer:
0.414 is the answer you needed
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