If the radius of the sphere is doubled, Find the ratio of volume of the new sphere to the original sphere.
Answers
Answered by
217
let the original radius be r
so the original volume = 4/3πr³
new radius = 2r
so new volume = 4/3π (2r)³ = 4/3 π (8r³)
ratio = 4/3πr³/4/3π (8r³)
= r³ / 8r³ = 1/8
so the ratio is 1:8
so the original volume = 4/3πr³
new radius = 2r
so new volume = 4/3π (2r)³ = 4/3 π (8r³)
ratio = 4/3πr³/4/3π (8r³)
= r³ / 8r³ = 1/8
so the ratio is 1:8
Answered by
59
let the original radius be r
so the original volume4/3Tr
new radius 2r
(2r)34/3 TT (8r5)
SOnew volume e4/3
ratio b4/3T /4/3T (8r)
- r3 /8rs1/8
so the ratio is 1:8
so the original volume4/3Tr
new radius 2r
(2r)34/3 TT (8r5)
SOnew volume e4/3
ratio b4/3T /4/3T (8r)
- r3 /8rs1/8
so the ratio is 1:8
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