if the radius of the sphere is increased by 10% then by what percent does the 1)surface area 2) volume increased
Answers
Answered by
2
Answer:
r
1
=
r
r
2
=
r
+
(
10
r
100
)
=
1.1
r
V
1
=
(
4
3
)
Π
r
3
V
2
=
(
4
3
)
Π
(
1.1
r
)
3
V
1
V
2
=
1
(
1.1
)
3
=
1
1.331
% increase in volume
[
(
V
2
−
V
1
)
V
1
]
×
100
=
[
(
V
2
V
1
)
−
1
]
×
100
=
[
1.331
−
1
]
×
100
=
0.331
×
100
=
33.1
%
Answered by
0
Answer:
r
1
=
r
r
2
=
r
+
(
10
r
100
)
=
1.1
r
V
1
=
(
4
3
)
Π
r
3
V
2
=
(
4
3
)
Π
(
1.1
r
)
3
V
1
V
2
=
1(1.1)3=11.331
% increase in volume [(V2−V1)V1]×100
=[(V2V1)−1]×100
=[1.331−1]×100
=0.331×100
=33.1
%
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