Math, asked by Ak11y, 1 year ago

if the radius of the sphere is increased by p % then find the percent increase in its surface area.

Answers

Answered by Anonymous
13
Hi Mate!!!

Surface area of Sphere is directly proportional to the square of radius.

Increase in itz surface area = 2 ( p% )

ppprakash1999: Increased in %=x-100
ppprakash1999: 100(1+p/100)^2-100
ppprakash1999: 100(1^2+p^2/10000+2p/100-1) by taking 100 common
ppprakash1999: 100(p^2÷10000+2p/100)
ppprakash1999: 100(p^2+200p/10000) by adding
ppprakash1999: P^2/100+200p/100 canceling 200by 100
ppprakash1999: (P^2/100+2p)%
ppprakash1999: Answer by harsh
Anonymous: its ans is 3p%
ppprakash1999: Read the question again
Answered by gadakhsanket
5

Hey Dear,

● Answer -

Percentage increase in surface area = 2p %

◆ Explanation -

# Given -

∆r/r = p %

∆A/A = ?

# Solution -

Surface area of sphere is given by -

A = 4πr²

Differentiating both sides -

∆A/A = 2 ∆r/r

∆A/A = 2 × p %

∆A/A = 2p %

Hence, percentage increase in surface area of sphere is 2p %.

Hope this helps you. Keep asking questions..

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