Question

If the radius upper part of frustum of a cone is 4 metre and the lower part of the same frustum is 2 metre height is 6 metre then the volume of frustum is what?

Answer 1

ok, the formula of the volume of the frustum is

$\frac{1}{3} \times \pi \times h \times ( {r1}^{2} + {r2}^{2} + r1r2)$

$= 2\pi(16 + 4 + 8) \\ = 56\pi$

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