Physics, asked by sbhumika630, 4 months ago


If the random error in the arithmetic mean of 50 observations is a, then the random error in the mean of 150 observations would be
1.a
2.3a
3.a/3
4.2a

Answers

Answered by Anonymous
30

Answer:

 \boxed{\mathfrak{3. \ \dfrac{a}{3}}}

Explanation:

On increasing the no. of observations n times, the random error reduces to  \sf \dfrac{1}{n} times.

So, if no. of observations are increased fro 50 to 150;

 \rm n =  \dfrac{150}{50}  \\  \\  \rm n = 3

Random error in the arithmetic mean of 50 observation = a

Random error becomes  \sf \dfrac{1}{n} times.

 \therefore Random error in the mean of 150 observation =  \sf \dfrac{a}{3} times

Answered by Anonymous
146

Explanation:

Given : -

  • If the random error in the arithmetic mean of 50 observations

To Find : -

  • e random error in the mean of 150 observations would be

Solution : -

The n random error is = a/n

substitute all values :

then the random error in the mean of 150

= 150 / 50

= 3

the mean of 150 observations would be

= a / 3

Option ( 3 .) is correct !

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