Math, asked by lopamudrasahu059, 9 months ago

plz solve this it's urgent ​

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Answered by shadowsabers03
1

So we're given,

\displaystyle\int e^a\ x\ dx

We know that 'e' is a constant. Since 'a' is not a function in x (relation between 'a' and 'x' is not defined in the question), we can say that e^a is a constant with respect to x. Thus we can take the constant out of the integral, and then we get that,

\displaystyle\int e^a\ x\ dx=e^a\int x\ dx

We know that,

\displaystyle\int x^n\ dx=\dfrac {x^{n+1}}{n+1},\ n\neq-1

If n=1, then,

\displaystyle\int x\ dx=\dfrac {x^2}{2}

Thus,

\displaystyle\boxed {\boxed {\int e^a\ x\ dx=\dfrac {e^a\cdot x^2}{2}+c}}

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