Find the four terms of the ap whose sum is 20 and the product of the extremes is 16
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Answer:
terms are 2 , 4, 6 & 8
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Step-by-step explanation:
let say 4 terms are
a , a+d , a+2d , a +3d
Sum = a + a+d + a +2d + a+3d = 4a +6d = 20
2a + 3d = 10
3d = 10 - 2a
a (a+3d) = 16
a (a + 10-2a) = 16
-a^2 + 10a = 16
a^2 - 10 + 16 = 0
(a-8)(a-2) = 0
a= 8 or a = 2
if a =8 then d = -2
if a = 2 then d =2
terms are 8 , 6 , 4 , 2
or 2 , 4 , 6 , 8
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