Question

If the ratio of boys to girls in a class is b and the ratio of girls to boys is g, then 3(b + g) is?

Answer 1

any comment ...welcome

Answer 2

3(b + g) is $3\left(\frac{B^{2}+G^{2}}{B G}\right)$

Step-by-step explanation:

Let us symbolize the number of boys with B and the number of girls with G.

Thus, from the problem we can understand that,

$\frac{B}{G}=b$

And

$\frac{G}{B}=g$

Hence, we get the relation between b and g, as:

$b=\frac{1}{g}$

Therefore, on substituting the value of b and g, we get,

$3(b+g)=3\left(\frac{B}{G}+\frac{G}{B}\right)$

Which results in the following:

$3(b+g)=3\left(\frac{B^{2}+G^{2}}{B G}\right)$