if the ratio of sun of n terms of two arithmetic progression is 7n+1:4n+27 then find the ratio of their 11th terms
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★ ARITHMETIC PROGRESSION ★
Given that :
Sum of two Ap's extensive to nth terms are aslike ,
7n + 1 : 4n + 27
Hence , it's ratio of 11th term extension will be given by ,
7 ( 2n -1 ) + 1 : 4 ( 2n - 1 ) + 27
HERE , n = 11
7 ( 21 ) + 1 : 4 ( 21 ) + 1
147 + 1 : 84 + 27
148 : 111
Hence , 148:111 is the required ratio
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Given that :
Sum of two Ap's extensive to nth terms are aslike ,
7n + 1 : 4n + 27
Hence , it's ratio of 11th term extension will be given by ,
7 ( 2n -1 ) + 1 : 4 ( 2n - 1 ) + 27
HERE , n = 11
7 ( 21 ) + 1 : 4 ( 21 ) + 1
147 + 1 : 84 + 27
148 : 111
Hence , 148:111 is the required ratio
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