Question

if the ratio of the sides of a rectangle made by turning a 42 cm long circular wire is 5 :6, what will be the length of the shorter side of the rectangle?​

Answer 1

Given:-

•Ratio of the sides of a rectangle made by turning a 42cm lon circular wire is 5:6.

To Find:-

•What is the length of the shorter side of the rectangle?

Solution:-

Let consider the length of the rectangle be 5x and breadth of the rectangle be 6x.

Using Formula:

$\: \: \sf \: perimeter \: of \: rectangle = circumference \: of \: circle \\ \\ \: \: \sf \: 2(length + breadth) = 2 \pi r$

Now substitute the values,

$\: \: \sf \: 2(6x + 5x) = 2 \times \frac{22}{7} \times 42 \\ \\ \: \: \sf \: 2 \times 11x = 2 \times 22 \times 6 \\ \\ \: \: \sf \: 22x = 264 \\ \\ \: \: \sf \therefore \: x = 12$

Hence,the value of x is 12.

Therefore,

• Length = 6x = 6 * 12 = 72cm
• Breadth = 5x= 5 *12 = 60cm

Shortest length is 60cm.

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