if the ratio of the sum of first n term of two aps is(7n+1):(4n+27) find the ratio of their mth term
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ATQ,
Sn/Sn'=7n+1/4n+27
Now
n/2[2a+(n-1)d]/n/2[2A+(n-1)D]
Replacing n by 2m-1
2a+(2m-2)d/2A+(2m-2)D=7(2m-1)+1/4(2m-1)+27
Therefore the ratio is
14m-6:8m+23
Sn/Sn'=7n+1/4n+27
Now
n/2[2a+(n-1)d]/n/2[2A+(n-1)D]
Replacing n by 2m-1
2a+(2m-2)d/2A+(2m-2)D=7(2m-1)+1/4(2m-1)+27
Therefore the ratio is
14m-6:8m+23
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