if the ratio of the sum of n termsof two A.P. is14n-4n:3n+5; find the ratio of their 8th terms
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sum of 8 terms of 1st AP=14n-4n=14(8)-4(8)=112-32=80
sum of 7 terms of 1st AP=14(7)-4(7)=98-28=70
8th term of 1st AP=80-70=10
sum of 8 term of 2 nd AP=3(8)+5=29
SUM OF 7 TERMS OF 2ND AP=3(7)+5=26
8th term of 2 nd AP=29-26=3
RATIO OF 8 th terms=10:3
sum of 7 terms of 1st AP=14(7)-4(7)=98-28=70
8th term of 1st AP=80-70=10
sum of 8 term of 2 nd AP=3(8)+5=29
SUM OF 7 TERMS OF 2ND AP=3(7)+5=26
8th term of 2 nd AP=29-26=3
RATIO OF 8 th terms=10:3
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