If the ratio of the sums of n terms of two A. P's is (7n+1):(4n+27), find the ratio of mth term
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Sn/S'n=(7n+1)/(4n+27)={n/2 (7n+1)}/{n/2 (4n+27)}={n/2 (2.4+(n-1) 7}/{n/2 (2.31/2+(n-1) 4}
now we create in formula Sn =n/2 {2a+(n-1)}
so, now
tm/t'm={4+(m-1) 7}/{31/2+(m-1) 4}
(7m-3)/(4m+23/2)
(14m-6)/(8m+23)
now we create in formula Sn =n/2 {2a+(n-1)}
so, now
tm/t'm={4+(m-1) 7}/{31/2+(m-1) 4}
(7m-3)/(4m+23/2)
(14m-6)/(8m+23)
abhi178:
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but answer is wrong
I think this is right
answer is (14m-6)/(8m+23)
please check answer again
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