Question

If the ratio of the volume of two cubes is 1: 8, then what will be the ratio of the area of ​​the base of the two cubes.

Answer 1

Answer:

1:4

Step-by-step explanation:

let volume of one cube be a³ and of the other's be b³

then,

a³:b³=1:8

=>a³/b³=1/8

=>(a/b)³=(1/2)³

=>a/b=1/2

=>(a/b)²=(1/2)²

=>a²/b²=1/4

=>area of base of one cube/area of base of another cube =1/4 [since, area of any side of cube is side²]

=>area of base of one cube: area of base of another cube=1:4

Answer 2

Here the ratio of volume of two cubes is 1:8

so lets volume of  first cube be x^3 and the volume of second cube be 8x^3( x^3 is because it the unit of volume)

so lets the length of length , breadth and height  of cube be x.

volume of first cube = x^3

    (side)^3 = x^3

     x^3   = x^3

  so, x=1

  now the volume of second cube is 8x^3

  lets its side be x

 (side)^3 = 8x^3

 so x = 2

now are of base of first cube = 1unit^3

and the are ao f base of second cube is 4 unit ^2

so the ratio i s1: 4

pls mark me as brainliest