Question

if the rdius of an tom of an element is 75 pm and the lattice is BCC the edge of unit cell will be

Answer 1

For bcc structure
Formula of radius=
$\sqrt{3} a \div 4 = radius \\ so \: a = 4r \div \sqrt{3 } \\ \: \: \: \: \: \: \: \: \: = (4 \times 75) \div \sqrt{3} \\ \: \: \: \: \: \: \: \: \: = 173.21$
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