Physics, asked by mahi1230, 9 months ago

if the reading of a torch bulb is 2.5 v and 500 ma then what will be (a) resistance ( b) power​

Answers

Answered by Anonymous
0

Answer:

Given :

Potential difference =V=5V

Current =I= 500mA=500x/1000 A=0.5 A

I) Power = V X I

= 5x0.5 =5x5/10=2.5 W

II)Reistance =R=?

By Ohm's law: V=IR

R=V/I

R=5/0.5

=50/5 =10 ohms

III)Energy consumed when it is lighted for 4 hours

Energy =Power x time

t=4hrs=4x60x60

=2.5x 4x60x60

=36000joules/sec

Answered by kikibuji
1

Answer:

refer this.............

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