calculare moles of O atoms in 9 grams of Mg(co3)2
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Answer:here it is
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Explanation:
144 g of mg(co3)2 contain → 96 g of oxygen atom
1 g of mg(C03)2 contain → 96/144 g of oxygen atom
9 g of mg(CO3)2 contain → (96/144) × 9 g of oxygen atom
=6 g of oxygen atom
∴ no.of moles of oxygen atom =given mass / GAM
= 6/16
=0.375 MOLES
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