Question

If the refracting angle of a prism is 60 degrees and minimum deviation is 30 degrees,the angle of incidence will be

Answer 1

Answer:

The required angle of incidence will be $45^{0}$

Explanation:

The angle formed by the two refracting sides of a prism with one another is known as the prism angle or refracting angle of a prism. This prism angle's refracting angle for an equilateral prism is equal to $60^{0}$.

The angle formed by the incident ray extending forward and the emerging ray extending backward is the angle of deviation of a prism.

Given: Refracting angle of the prism $A=60^{0}$

To find: The objective is to find out the angle of incidence.

Solution:

Given, refracting angle of the prism $A=60^{0}$

Minimum deviation δ$=30^{0}$

δ$=2i-A$

$i=\frac{30^{0} +60^{0} }{2} \\=45^{0}$

Therefore, the angle of incidence will be $45^{0}$.

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Answer 2

Angle of incidence is i = 45°

Given

refracting angle of a prism is 60 degrees

minimum deviation is 30 degrees

To Find

We need to find the angle of incidence

Solution

• The angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal.
• The smallest angle through which light is bent by an optical element or system is called minimum deviation.
• The angle formed due to two lateral faces of the prism is known as the angle of prism.

Here,

refracting angle of prism A = 60°

Minimum deviation δ=30°

We know,

                   δ =  2i−A    

                30° = 2 i - 60°

                  2i = 90°

                    i = 45°

i.e. Angle of incidence is i = 45°

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