Question

If the remainder on division of x^3+2x^2+kx+3 is 21 by (x – 3) is 21, find the quotient
and the value of k,

Answer 1

Answer:

applying remainder theorem...

x-3=0

X=3

now ..let....p(X)=x^3+2x^2+kx+3

therefore ..p(3)=3^3+2(3)^2+k(3)+3=21

=>3k=21-48=-27

• k=-9

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Answer 2

Answer:

k= -9

Step-by-step explanation:

p(x)=3

(3)^3+2(3)^2+k(3)+3=21

27+18+3k+3=21

48+3k=21

3k=21-48

3k=-27

k=-27/3

k=-9