Question

If the remainder on division of x2 + 2x2 + kx + 3 by x- 3 is 21 find the quotient and the value of k

Answer 1

Hello Dear!!!!

Here's your answer....

Let,

f(x) = (x)^2 + 2(x)^2 + kx + 3 

g(x) = x-3

zero of x-3 is

x-3 = 0

x= 3

subsitute x=3 in f(x)

(x)^2 + 2(x)^2 + kx + 3 

(3)^2 + 2(3)^2 + k(3) + 3 = 21

9 + 18 + 3k + 3 = 21

30 + 3k = 21

3k = 21-30

3k = -9

k = -9/3

k = -3

The value of k is -3

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HOPE THIS HELPS YOU.....