Question

If the remainder, when x^3 -ax^2 +11x -6 is divided by x-4 is 6, then the value of 'a' is:

Answer 1

Answer:

IT IS VERY EASY BRO.

GIVEN,

p(x)=x3-ax2+11x-6

g(x)=0

x-4=0

x=4

NOW,

4^3-a4^2+11(4)-6=6 [AS 6 IS THE REMAINDER OR r(x)]

64-16a+44-6=6

108-6-16a=6

102-16a=6

-16a=6-102

-16a=-96

a=(-96)÷(-16)

a=6

THEREFORE,THE VALUE OF a IS 6