if the resistance of conducting wire P is 4 times resistance of conducting wire Q then the ratio of cross-sectional areas of wires is a.1:2, b.1:4, c. 1:8,d.1:6 which is correct one
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fHEYA.......✌✌✌✌
HERE IS YOUR ANSWER..........
1:4 IS the answer
optionB
HERE IS YOUR ANSWER..........
1:4 IS the answer
optionB
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bro! see R=,roo ×L/ A. see in this formula resistance is inversely proportional to area . so r1/r2 =a2/a1 so,4r/r = a2 /a1 then a1/ a2 = 1/4. hope you understand please mark brainliest.
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