If the resistance of the conductor is reduced to half its initial value , then the heating effect in the conductor Will become....
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Answered by
4
There are lot of formula to find heat produced in the conductor.
P = I²R , P = VI , P = V²/R
which one should be used ? confusion ?
Don't be confuse dud , just use P = V²/R.
because here question didn't say about altering of voltage. means, voltage remains same. hence, we should Power = V²/R.
now tell me , when resistance of a conductor is reduced to half , then power should be ?
of course , double
because power is inversely proportional to resistance , if resistance is reduced to haft then power will be double.
hence, the power is doubled
you can say that heat produced by conductor is doubled
P = I²R , P = VI , P = V²/R
which one should be used ? confusion ?
Don't be confuse dud , just use P = V²/R.
because here question didn't say about altering of voltage. means, voltage remains same. hence, we should Power = V²/R.
now tell me , when resistance of a conductor is reduced to half , then power should be ?
of course , double
because power is inversely proportional to resistance , if resistance is reduced to haft then power will be double.
hence, the power is doubled
you can say that heat produced by conductor is doubled
Answered by
10
If the resistance of the conductor is reduced to half its initial value, then the heating effect in the conductor will become half.
The formula of Heat will be, H = I^2 * R * T
Hnew = I^2 * R/2 * T
H new = ½ * I^2 * R * T
Hnew = ½ * H
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