Question

if the root of equation x ^2+6x+k=0 is h+2×square root of 6 then find the value of h and k.​

Answer 1

Answer:

x²+6x+k=0

b²-4ac=0

(6)²-4*1*k

36-4k

36=4k

36/4=k

9=k

Step-by-step explanation:

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Answer 2

Given,

${x}^{2} + 6x + k = 0$

Compare the equation in ax^2+bx+c=0

a=1 , b=6 , c=k

b^2-4ac=0

6^2-4×1×k=0

36-4k=0

36=4k

k=9

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