if the root of quadratic equation kx square - 7 x + 12 is equal to zero is 3 find the value of k
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Answer:k= 1
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X=3
kx^2 -7x +12 =0 comparing equation with ax^2 +bx +c =0
a = k , b = -7 , c = 12
b^2 -4ac = (-7)^2 - 4 k( 12)
= 49 - 48k
but , b^2 - 4ac =0
49 - 48 k = 0
-48k = -49
48k = 49
k = 49 /48
himanshu9727:
thank u so much
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